Optimal. Leaf size=165 \[ -\frac{3 c^4 \sqrt{b x^2+c x^4}}{256 b^3 x^3}+\frac{c^3 \sqrt{b x^2+c x^4}}{128 b^2 x^5}+\frac{3 c^5 \tanh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{b x^2+c x^4}}\right )}{256 b^{7/2}}-\frac{c^2 \sqrt{b x^2+c x^4}}{160 b x^7}-\frac{3 c \sqrt{b x^2+c x^4}}{80 x^9}-\frac{\left (b x^2+c x^4\right )^{3/2}}{10 x^{13}} \]
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Rubi [A] time = 0.254928, antiderivative size = 165, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 4, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.21, Rules used = {2020, 2025, 2008, 206} \[ -\frac{3 c^4 \sqrt{b x^2+c x^4}}{256 b^3 x^3}+\frac{c^3 \sqrt{b x^2+c x^4}}{128 b^2 x^5}+\frac{3 c^5 \tanh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{b x^2+c x^4}}\right )}{256 b^{7/2}}-\frac{c^2 \sqrt{b x^2+c x^4}}{160 b x^7}-\frac{3 c \sqrt{b x^2+c x^4}}{80 x^9}-\frac{\left (b x^2+c x^4\right )^{3/2}}{10 x^{13}} \]
Antiderivative was successfully verified.
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Rule 2020
Rule 2025
Rule 2008
Rule 206
Rubi steps
\begin{align*} \int \frac{\left (b x^2+c x^4\right )^{3/2}}{x^{14}} \, dx &=-\frac{\left (b x^2+c x^4\right )^{3/2}}{10 x^{13}}+\frac{1}{10} (3 c) \int \frac{\sqrt{b x^2+c x^4}}{x^{10}} \, dx\\ &=-\frac{3 c \sqrt{b x^2+c x^4}}{80 x^9}-\frac{\left (b x^2+c x^4\right )^{3/2}}{10 x^{13}}+\frac{1}{80} \left (3 c^2\right ) \int \frac{1}{x^6 \sqrt{b x^2+c x^4}} \, dx\\ &=-\frac{3 c \sqrt{b x^2+c x^4}}{80 x^9}-\frac{c^2 \sqrt{b x^2+c x^4}}{160 b x^7}-\frac{\left (b x^2+c x^4\right )^{3/2}}{10 x^{13}}-\frac{c^3 \int \frac{1}{x^4 \sqrt{b x^2+c x^4}} \, dx}{32 b}\\ &=-\frac{3 c \sqrt{b x^2+c x^4}}{80 x^9}-\frac{c^2 \sqrt{b x^2+c x^4}}{160 b x^7}+\frac{c^3 \sqrt{b x^2+c x^4}}{128 b^2 x^5}-\frac{\left (b x^2+c x^4\right )^{3/2}}{10 x^{13}}+\frac{\left (3 c^4\right ) \int \frac{1}{x^2 \sqrt{b x^2+c x^4}} \, dx}{128 b^2}\\ &=-\frac{3 c \sqrt{b x^2+c x^4}}{80 x^9}-\frac{c^2 \sqrt{b x^2+c x^4}}{160 b x^7}+\frac{c^3 \sqrt{b x^2+c x^4}}{128 b^2 x^5}-\frac{3 c^4 \sqrt{b x^2+c x^4}}{256 b^3 x^3}-\frac{\left (b x^2+c x^4\right )^{3/2}}{10 x^{13}}-\frac{\left (3 c^5\right ) \int \frac{1}{\sqrt{b x^2+c x^4}} \, dx}{256 b^3}\\ &=-\frac{3 c \sqrt{b x^2+c x^4}}{80 x^9}-\frac{c^2 \sqrt{b x^2+c x^4}}{160 b x^7}+\frac{c^3 \sqrt{b x^2+c x^4}}{128 b^2 x^5}-\frac{3 c^4 \sqrt{b x^2+c x^4}}{256 b^3 x^3}-\frac{\left (b x^2+c x^4\right )^{3/2}}{10 x^{13}}+\frac{\left (3 c^5\right ) \operatorname{Subst}\left (\int \frac{1}{1-b x^2} \, dx,x,\frac{x}{\sqrt{b x^2+c x^4}}\right )}{256 b^3}\\ &=-\frac{3 c \sqrt{b x^2+c x^4}}{80 x^9}-\frac{c^2 \sqrt{b x^2+c x^4}}{160 b x^7}+\frac{c^3 \sqrt{b x^2+c x^4}}{128 b^2 x^5}-\frac{3 c^4 \sqrt{b x^2+c x^4}}{256 b^3 x^3}-\frac{\left (b x^2+c x^4\right )^{3/2}}{10 x^{13}}+\frac{3 c^5 \tanh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{b x^2+c x^4}}\right )}{256 b^{7/2}}\\ \end{align*}
Mathematica [C] time = 0.0180447, size = 46, normalized size = 0.28 \[ \frac{c^5 \left (x^2 \left (b+c x^2\right )\right )^{5/2} \, _2F_1\left (\frac{5}{2},6;\frac{7}{2};\frac{c x^2}{b}+1\right )}{5 b^6 x^5} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.071, size = 186, normalized size = 1.1 \begin{align*}{\frac{1}{1280\,{x}^{13}{b}^{5}} \left ( c{x}^{4}+b{x}^{2} \right ) ^{{\frac{3}{2}}} \left ( 15\,{b}^{3/2}\ln \left ( 2\,{\frac{\sqrt{b}\sqrt{c{x}^{2}+b}+b}{x}} \right ){x}^{10}{c}^{5}-5\, \left ( c{x}^{2}+b \right ) ^{3/2}{x}^{10}{c}^{5}+5\, \left ( c{x}^{2}+b \right ) ^{5/2}{x}^{8}{c}^{4}-15\,\sqrt{c{x}^{2}+b}{x}^{10}b{c}^{5}+10\, \left ( c{x}^{2}+b \right ) ^{5/2}{x}^{6}b{c}^{3}-40\, \left ( c{x}^{2}+b \right ) ^{5/2}{x}^{4}{b}^{2}{c}^{2}+80\, \left ( c{x}^{2}+b \right ) ^{5/2}{x}^{2}{b}^{3}c-128\, \left ( c{x}^{2}+b \right ) ^{5/2}{b}^{4} \right ) \left ( c{x}^{2}+b \right ) ^{-{\frac{3}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (c x^{4} + b x^{2}\right )}^{\frac{3}{2}}}{x^{14}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.48118, size = 528, normalized size = 3.2 \begin{align*} \left [\frac{15 \, \sqrt{b} c^{5} x^{11} \log \left (-\frac{c x^{3} + 2 \, b x + 2 \, \sqrt{c x^{4} + b x^{2}} \sqrt{b}}{x^{3}}\right ) - 2 \,{\left (15 \, b c^{4} x^{8} - 10 \, b^{2} c^{3} x^{6} + 8 \, b^{3} c^{2} x^{4} + 176 \, b^{4} c x^{2} + 128 \, b^{5}\right )} \sqrt{c x^{4} + b x^{2}}}{2560 \, b^{4} x^{11}}, -\frac{15 \, \sqrt{-b} c^{5} x^{11} \arctan \left (\frac{\sqrt{c x^{4} + b x^{2}} \sqrt{-b}}{c x^{3} + b x}\right ) +{\left (15 \, b c^{4} x^{8} - 10 \, b^{2} c^{3} x^{6} + 8 \, b^{3} c^{2} x^{4} + 176 \, b^{4} c x^{2} + 128 \, b^{5}\right )} \sqrt{c x^{4} + b x^{2}}}{1280 \, b^{4} x^{11}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (x^{2} \left (b + c x^{2}\right )\right )^{\frac{3}{2}}}{x^{14}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.2302, size = 149, normalized size = 0.9 \begin{align*} -\frac{1}{1280} \, c^{5}{\left (\frac{15 \, \arctan \left (\frac{\sqrt{c x^{2} + b}}{\sqrt{-b}}\right )}{\sqrt{-b} b^{3}} + \frac{15 \,{\left (c x^{2} + b\right )}^{\frac{9}{2}} - 70 \,{\left (c x^{2} + b\right )}^{\frac{7}{2}} b + 128 \,{\left (c x^{2} + b\right )}^{\frac{5}{2}} b^{2} + 70 \,{\left (c x^{2} + b\right )}^{\frac{3}{2}} b^{3} - 15 \, \sqrt{c x^{2} + b} b^{4}}{b^{3} c^{5} x^{10}}\right )} \mathrm{sgn}\left (x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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